## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 2 - Exercises and Problems: 60

#### Answer

a) 21.3 meters per second b) 2.6 seconds

#### Work Step by Step

a) We simplify the equation for final velocity in order to find the initial velocity: $v_0 = \sqrt{v_f^2 - 2a\Delta x}$ $v_0 = \sqrt{5^2 - 2(-6.3)(34)}=\fbox{21.3 meters per second}$ b) We find the change in time: $t = \frac{5-21.3}{-6.3}=\fbox{2.6 seconds}$

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