Answer
a) $1.5\times10^{3}\,m/s$
b) 0
Work Step by Step
a) Velocity of the women relative to the ground $v_{g}= 90 km/h=\frac{90 \times1000m}{h}\times\frac{1\,h}{3600\,s}=25\,m/s$
m= 60 kg
$p_{g}= mv_{g}=60.\,kg\times25\,m/s=1.5\times10^{3}\,kg\,m/s$
b) Velocity of the women with respect to the car is 0.
Therefore, p relative to car= $m\times0=0$
