Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 215: 5

$5.88 \space Kg.m/s$

The change in the ball's momentum can be determined as follows: $\Delta p=m\Delta V$ $\implies \Delta p=m(v_f-v_i)$ We plug in the known values to obtain: $p=0.150(-34.7-4.50)$ (final velocity is taken as negative due to its opposite direction) This simplifies to: $p=-5.88 \space Kg.m/s$ Thus the required magnitude is : $5.88 \space Kg.m/s$