College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 215: 10

Answer

(a) If they are running in the same direction then $v_2=3.5m/s$ (b) If they are running in the opposite direction then $v_2=8.17m/s$

Work Step by Step

There are two cases (a) They are running in the same direction (b) in the opposite direction (a) The velocity of the lighter runner can be determined as follows: Given that $P_1+P_2=350$ $\implies P_2=350-P_1$ $P_2=350-m_1v_1$ $\implies P_2=350-70(2)=210Kg.m/s$ $\implies m_2v_2=210$ $\implies v_2=\frac{210}{60}$ $\implies v_2=3.5m/s$ (b) If they are running in the opposite direction then $P_2-P_1=350Kg.m/s$ $P_2=P_1+350=140+350=490$ $\implies m_2v_2=490$ $\implies v_2=\frac{490}{m_2}$ We plug in the known values to obtain: $v_2=\frac{490}{60}$ $\implies v_2=8.17m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.