Answer
(a) $10.6 \space Kg.m/s$ and the direction of the momentum is opposite to the velocity of ball
(b) $F_{avg}=2.26\times 10^3N$
Work Step by Step
(a) As we know that
$\Delta P=m\Delta v$
$\implies \Delta P=m(v_f-v_i)$
We plug in the known values to obtain:
$\Delta P=0.25(0-42.2)$ Final velocity is zero because the ball comes to rest.
$\implies \Delta P=-10.6 \space Kg.m/s$
The negative sign shows that the direction of the change in momentum is opposite to that of the velocity.
(b) The required average force can be determined as follows:
$F_{avg}=\frac{\Delta P}{\Delta t}$
We plug in the known values to obtain:
$F_{avg}=\frac{10.6}{0.0047}$
$\implies F_{avg}=2.26\times 10^3N$
