College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 215: 14

Answer

$F_{avg}=68.4N$

Work Step by Step

We can find the average force as follows: First of all, we will find the velocity when the ball hits the ground $v^2=v_i^2+2gh$ (Initially, the ball falls from rest therefore $v_i=0$) $\implies v^2=2gh$ $\implies v=\sqrt{2gh}$ We plug in the known values to: $v=\sqrt{2(9.8)(15)}=17.1m/s$ We take $v=-17.1m/s$ because the ball is falling downward. Now $F_{avg}=\frac{m(v_f-v_i)}{\Delta t}$ We plug in the known values to obtain: $F_{avg}=\frac{2(0-(-17.1))}{0.5}$ This simplifies to: $F_{avg}=68.4N$
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