Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 215: 8

$\Delta p=88200Ns$

As we know that $F_{avg}=\frac{\Delta p}{\Delta t}$ This can be rearranged as: $\Delta p=F_{avg}\Delta t$ $\implies \Delta p=mg \Delta t$ We plug in the known values to obtain: $\Delta p=75 \times 9.8\times 120$ ( $As \space t=2min =120s$) This simplifies to: $\Delta p=88200Ns$