## College Physics (4th Edition)

It will take $79.7~seconds$
We can find the amount of heat required to raise the temperature by $80.0~ C^{\circ}$: $Q = m~c~\Delta T$ $Q = (0.50~kg)(4186~J/kg~C^{\circ})(80.0~C^{\circ})$ $Q = 1.6744\times 10^5~J$ The amount of heat required is $1.6744\times 10^5~J$ We can find the time required to provide this amount of heat: $t = \frac{Q}{P} = \frac{1.6744\times 10^5~J}{2100~W} = 79.7~s$ It will take $79.7~seconds$.