College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 534: 25


It will take $79.7~seconds$

Work Step by Step

We can find the amount of heat required to raise the temperature by $80.0~ C^{\circ}$: $Q = m~c~\Delta T$ $Q = (0.50~kg)(4186~J/kg~C^{\circ})(80.0~C^{\circ})$ $Q = 1.6744\times 10^5~J$ The amount of heat required is $1.6744\times 10^5~J$ We can find the time required to provide this amount of heat: $t = \frac{Q}{P} = \frac{1.6744\times 10^5~J}{2100~W} = 79.7~s$ It will take $79.7~seconds$.
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