College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 534: 19

Answer

(a) The heat capacity of the system is $382~J/C^{\circ}$ (b) The heat capacity of the system is $32,070~J/C^{\circ}$

Work Step by Step

(a) The heat capacity $C$ is the amount of heat required to raise the temperature by $1~ C^{\circ}$. We can find the heat capacity of the system: $C = m_w~c_w+m_b~c_b$ $C = (0.050~kg)(4186~J/kg~C^{\circ})+(0.450~kg)(384~J/kg~C^{\circ})$ $C = 382~J/C^{\circ}$ The heat capacity of the system is $382~J/C^{\circ}$ (b) The heat capacity $C$ is the amount of heat required to raise the temperature by $1~ C^{\circ}$. We can find the heat capacity of the system: $C = m_w~c_w+m_a~c_a$ $C = (7.5~kg)(4186~J/kg~C^{\circ})+(0.75~kg)(900~J/kg~C^{\circ})$ $C = 32,070~J/C^{\circ}$ The heat capacity of the system is $32,070~J/C^{\circ}$
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