College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 534: 20


The amount of heat required is $7.42\times 10^5~J$

Work Step by Step

We can find the amount of heat required to raise the temperature by $85.0~ C^{\circ}$: $Q = m_w~c_w~\Delta T+m_a~c_a~\Delta T$ $Q = (2.00~kg)(4186~J/kg~C^{\circ})(85.0~C^{\circ})+(0.400~kg)(900~J/kg~C^{\circ})(85.0~C^{\circ})$ $Q = 7.42\times 10^5~J$ The amount of heat required is $7.42\times 10^5~J$
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