Answer
$502,320~J$ of heat must flow into the water.
Work Step by Step
We can find the mass of the water:
$m = (1000~kg/m^3)(2.0\times 10^{-3}~m^3) = 2.0~kg$
We can find the required heat:
$Q = m~c~\Delta T$
$Q = (2.0~kg)(4186~J/kg~C^{\circ})(60.0~C^{\circ})$
$Q = 502,320~J$
$502,320~J$ of heat must flow into the water.
