## College Physics (4th Edition)

The heat capacity of 20.0 kg of silver is $4600~J$
The heat capacity is the amount of heat needed to raise the temperature by $1~ C^{\circ}$. We can find the heat capacity of 20.0 kg of silver: $Q = m~c~\Delta T$ $Q = (20.0~kg)(230~J/kg~C^{\circ})(1~C^{\circ})$ $Q = 4600~J$ The heat capacity of 20.0 kg of silver is $4600~J$