Answer
The heat capacity of 20.0 kg of silver is $4600~J$
Work Step by Step
The heat capacity is the amount of heat needed to raise the temperature by $1~ C^{\circ}$. We can find the heat capacity of 20.0 kg of silver:
$Q = m~c~\Delta T$
$Q = (20.0~kg)(230~J/kg~C^{\circ})(1~C^{\circ})$
$Q = 4600~J$
The heat capacity of 20.0 kg of silver is $4600~J$
