College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 534: 15


$v = 100~m/s$

Work Step by Step

We can find the man's speed: $K = Q$ $\frac{1}{2}mv^2 = Q$ $v^2 = \frac{2Q}{m}$ $v = \sqrt{\frac{2Q}{m}}$ $v = \sqrt{\frac{(2)(418\times 10^3~J)}{83~kg}}$ $v = 100~m/s$
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