College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 534: 22


The specific heat of lead is $126~J/kg~C^{\circ}$

Work Step by Step

We can find the specific heat of lead: $Q = m~c~\Delta T$ $c = \frac{Q}{m~\Delta T}$ $c = \frac{880~J}{(0.350~kg)(20.0~C^{\circ})}$ $c = 126~J/kg~C^{\circ}$ The specific heat of lead is $126~J/kg~C^{\circ}$
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