Answer
(a) 0.069 M
(b) 0.0157 M
(c) 0.423 M
Work Step by Step
Molarity = Number of moles/ Volume (in L)
Molarity = (Number of moles X 1000) / Volume (in mL)
(a) 1.54 mol of LiCl in 22.2 L of solution
= 1.54 / 22.2
= 0.069 M
(b) 0.101 mol of $LiNO_{3}$ in 6.4 L of solution
= 0.101 / 6.4
= 0.0157 M
(c) 0.0323 mol of glucose in 76.2 mL of solution
= 0.0323 / 0.0762
= 0.423 M
