Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems: 50

Answer

a. 0.213 g KCl. b. 4.34x$10^3$ g KCl c. 4.6x$10^-3$ g KCl.

Work Step by Step

Mass percent is the number of grams of solute per 100g of solution. a. So a solution with a concentration of 1.08% KCl by mass per 100 g of solution. Hence 19.7 g of solution contains: (1.08g KCl./100g solution)x 19.7g solution = 0.213 g KCl. b. So a solution with a concentration of 18.7% KCl by mass per 100 g of solution. Hence 23.2 g of solution contains: (18.7g KCl./100g solution)x 23.2 kg solution = 4.34x$10^3$ g KCl c. So a solution with a concentration of 12% KCl by mass per 100 g of solution. Hence 38 mg of solution contains: (12 g KCl./100g solution)x 38 mg solution = 4.6x$10^-3 $ g KCl.
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