Answer
1.6x$10^2$ g
Work Step by Step
Since 1 L AgNO3 contains = 1000 mL AgNO3.
So 4.8 L AgNO3 contains = 4800 mL AgNO3
4800 mL of AgNO3 solution contains 4800mL of silver.
Hence
Mass of solution = Volume of solution x density of solution
Density of solution = 1.01 g/mL.
Mass of 4800 mL of silver solution =4800mL x 1.01g/mL= 4848g silver.
Mass percent is the number of grams of solute per 100g of solution. A solution with a concentration of 3.4% silver per 100 g of solution. Hence 4848g of solution are present. This gives:
= (3.4g silver/100 g solution)x 4848g solution
= 1.6x$10^2$ g AgNO3.
