Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 480: 59

Answer

(a) 0.193 M (b) 0.234 M (c) 0.407 M

Work Step by Step

Molarity = Number of moles/ Volume (in L) Molarity = (Number of moles X 1000) / Volume (in mL) (a) 0.127 mol of sucrose in 655 mL of solution = 0.127/0.655 = 0.193 M (b) 0.205 mol of KNO3 in 0.875 L of solution = 0.205/0.875 = 0.234 M (c) 1.1 mol of KCl in 2.7 L of solution = 1.1 / 2.7 = 0.407 M
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