Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems: 49

Answer

a. 1.8 g sucrose b. 1x$10^{-2}$ g sucrose c. 0.46x$10^3$ g sucrose

Work Step by Step

Mass percent is the number of grams of solute per 100g of solution. a. A solution with a concentration of 3.7% sucrose by mass contains 3.7g of sucrose per 100 g of solution. Hence 48g of solution contains: (3.7g sucrose/100g of solution) x 48 g solution = 1.8g sucrose b. So a solution with a concentration of 10.2% sucrose by mass contains 10.2g of sucrose per 100 g of solution. Hence 103 mg of solution contains: (10.2g sucrose/100g of solution) x 103 mg solution x $10^-3$ g/1mg) = 1x$10^-2$ g sucrose c. So a solution with a concentration of 14.3% sucrose by mass contains 14.3g of sucrose per 100 g of solution. Hence 3.2 kg of solution contains: (14.3g sucrose/100g of solution) x 3.2 kg solution x $10^3$ g/1mg = 0.46x$10^3$ g sucrose
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