Answer
(a) 18.08%
(b) 0.779 %
(c) 10.28%
Work Step by Step
Mass percent = (Mass solute X 100)/ (Mass solute + Mass solvent)
(a) 132 g KCl in 598 g $H_{2}O$
= (132 X 100)/ (132 + 598)
= 13200/730
= 18.08%
(b) 22.3 mg $KNO_{3}$ in 2.84 g $H_{2}O$
= (0.0223 X 100)/(0.0223+2.84)
= 2.23/ 2.8623
= 0.779 %
(c) 8.72 g $C_{2}HO$ in 76.1 g $H_{2}O$
= (8.72 X 100)/(8.72 + 76.1)
= 872/84.82
= 10.28%
