Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems: 56

Answer

14117.65 g

Work Step by Step

It is given that a hard water sample contains 0.0085% Ca by mass. So, 0.0085 g of Ca is present in 100 g of water. For 1.2 g of Ca → ? = (100 X 1.2)/(0.0085) = 14117.6471 g of water = 14117.65 g
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