Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.19c


$C_8H_8(l)+10O_2(g)\rightarrow 8CO_2+4H_2O$

Work Step by Step

Combustion means $O_2$ is the other reactant. The unbalanced equation is: $C_8H_8(l)+O_2(g)\rightarrow CO_2+H_2O$ Add a coefficient of 8 to $CO_2$ to balance $C$. Add a coefficient of 4 to $H_2O$ to balance $H$. $C_8H_8(l)+O_2(g)\rightarrow 8CO_2+4H_2O$ The right side now has 20 $O$ atoms. Add a coefficient of 10 to $O_2$ to balance. $C_8H_8(l)+10O_2(g)\rightarrow 8CO_2+4H_2O$
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