Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.23b



Work Step by Step

The molecular mass of $KMnO_4$ can be found as follows: Making the sum of the multiplication of the atomic mass of each by the element by the quantity of atoms of the element in the substance. As shown below. MM ($KMnO_4$) = $(1\times39)+(1\times24)+(4\times16)= 124u$
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