Answer
$2C_{3}H_{7}OH (l) + 9O_{2} (g) → 6CO_{2} + 8H_{2}O$
Work Step by Step
This is the chemical equation before balancing:$C_{3}H_{7}OH (l) + O_{2} (g) → CO_{2} + H_{2}O$
Add coefficient of 4 to $H_{2}O$ to balance $H$: $C_{3}H_{7}OH (l) + O_{2} (g) → CO_{2} + 4H_{2}O$
Add coefficient of 3 to $CO_{2}$ to balance out $C$:
$C_{3}H_{7}OH (l) + O_{2} (g) → 3CO_{2} + 4H_{2}O$
Add coefficient of 4.5 to $O_{2}$ to balance out $O$:
$C_{3}H_{7}OH (l) + 4.5O_{2} (g) → 3CO_{2} + 4H_{2}O$
But, you can't have coefficients that are not whole numbers, so double all coefficients to get $2C_{3}H_{7}OH (l) + 9O_{2} (g) → 6CO_{2} + 8H_{2}O$, your final answer.
