Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.20c


$2C_{3}H_{7}OH (l) + 9O_{2} (g) → 6CO_{2} + 8H_{2}O$

Work Step by Step

This is the chemical equation before balancing:$C_{3}H_{7}OH (l) + O_{2} (g) → CO_{2} + H_{2}O$ Add coefficient of 4 to $H_{2}O$ to balance $H$: $C_{3}H_{7}OH (l) + O_{2} (g) → CO_{2} + 4H_{2}O$ Add coefficient of 3 to $CO_{2}$ to balance out $C$: $C_{3}H_{7}OH (l) + O_{2} (g) → 3CO_{2} + 4H_{2}O$ Add coefficient of 4.5 to $O_{2}$ to balance out $O$: $C_{3}H_{7}OH (l) + 4.5O_{2} (g) → 3CO_{2} + 4H_{2}O$ But, you can't have coefficients that are not whole numbers, so double all coefficients to get $2C_{3}H_{7}OH (l) + 9O_{2} (g) → 6CO_{2} + 8H_{2}O$, your final answer.
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