## Chemistry: The Central Science (13th Edition)

The represented molecule is Methanol ($C_{}H_{3}O_{}H_{}$) 1. Find the mass of $C_{}H_{3}O_{}H_{}$: C: 12 x 1 = 12 H: 1 x 4 = 4 O: 16 x 1 = 16 16 + 4 + 12 = 32 2. Divide the mass of Carbon in the molecule by the total mass: $\frac{12}{32}$ = 0.375 3. Multiply the result by 100%: 0.375 x 100% = 37.5%