Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.25c



Work Step by Step

The percentage of oxygen in the substance is determined by the following equation: $\%O = \frac{4\times16}{303}\times100\%=21,12\%$ Knowing that, 4 = number of oxygen atoms 16 = molecular mass of oxygen 303 = molecular weight of cocaine
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