## Chemistry: The Central Science (13th Edition)

The represented molecule is Ethane ($C_{2}H_{6}$) 1. Find the mass of $C_{2}H_{6}$: C: 12 x 2 = 24 H: 1 x 6 = 6 24 + 6 = 30 2. Divide the mass of Carbon in the molecule by the total mass: $\frac{24}{30}$ = 0.8 3. Multiply the result by 100%: 0.8 x 100% = 80%