Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 17 - Additional Aspects of Aqueous Equilibria - Exercises - Page 768: 17.21a

Answer

$pH=3.82$

Work Step by Step

By using the Henderson-Hasselbach equation $(pH=pKa + log ([A-]/[HA])$, and considering that the Ka of lactic acid is 1.38E-4, we get that $pH=-log(1.38E-4) + log(.11/.12)=3.82$.
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