Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 717: 16.25c


Products : $HNO_2$ and $OH^-$. The left side will be favored.

Work Step by Step

$H_2O$ will give one proton to $N{O_2}^-$. $N{O_2}^-(aq) + H_2O(l) HNO_2(aq) + OH^-(aq)$ Since $HNO_2$$(Ka = 4.5 \times 10^{-4})$ is stronger than $N{O_2}^-$$(Kb = 2.2 \times 10^{-11})$, the left side will be favored.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.