Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises: 16.19a

Answer

Acting like an Acid: $H{SO_3}^-(aq) + H_2O(l) --> S{O_3}^{2-}(aq) + H_3O^+(aq)$ Acting like a Base: $H{SO_3}^-(aq) + H_2O(l) --> H_2{SO_3}(aq) + OH^{-}(aq)$

Work Step by Step

When the ion acts like an Acid, it gives one proton to water: $H{SO_3}^-(aq) + H_2O(l) --> {SO_3}^{2-}(aq) + H_3O^+(aq)$ When the ion acts like a Base, it receives one proton from water: $H{SO_3}^-(aq) + H_2O(l) --> H_2{SO_3}(aq) + OH^{-}(aq)$
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