Answer
${H_2C_6H_7O_5}^-(aq) + H_2O(l) -> H_3C_6H_7O_5(aq) + OH^-(aq) $
Work Step by Step
If ${H_2C_6H_7O_5}^-(aq)$ is going to act like a base, it will receive a $H^+$ from water:
${H_2C_6H_7O_5}^-(aq) + H_2O(l) -> H_3C_6H_7O_5(aq) + OH^-(aq) $
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 16 - Acid-Base Equilibria - Exercises - Page 717: 16.20a
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