Answer
$(i) : {HSO_4}^-$
$(ii) : {CH_3NH_3}^+$
Work Step by Step
Write the reactions were ${SO_4}^{2-}$ and $CH_3NH_2$ act like bases:
$(i) : {SO_4}^{2-} + H_2O --> H{SO_4}^- + OH^-$
$(ii) : {CH_3NH_2} + H_2O --> {CH_3NH_3}^+ + OH^-$
The acids formed in these reactions are the conjugated acids.
