Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises: 16.21a

Answer

$CH_3COO^-$ is a weak base; Conjugate acid: $CH_3COOH$, which is a weak acid.

Work Step by Step

$CH_3COO^-(aq) + H_2O (l) --> CH_3COOH(aq) + OH^-(aq)$ As we can see, $CH_3COOH$ is the conjugate acid of $CH_3COO^-$. Since $CH_3COO^-$ is a weak base (but not insignificant), his conjugate acid will be weak too.
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