## Chemistry: The Central Science (13th Edition)

The product will be $2OH^-$. The rigth side (Product) will be favored.
$O^{2-}$ is a strong base, so it will react with water to produce $OH^-$ $O^{2-}(aq) + H_2O(l) OH^-(aq) + OH^-(aq)$ Since $O^{2-}$ is a strong base, and $OH^-$ a very weak acid, the right side will be favored.