Answer
$(i) = {IO_3}^-$
$(ii) = NH_3$
Work Step by Step
1. Write the equations, where the acids gives one $H^+$ to water:
$(i) = HIO_3 + H_2O -> {IO_3}^- + H_3O^+$
$(ii) = {NH_4}^+ + H_2O -> NH_3 + H_3O^+$
Now we know that ${IO_3}^-$ and $NH_3$ are the conjugate bases.
