Answer
501 mL
Work Step by Step
$P_{1}=165\, mmHg$
$V_{1}=754\,mL$
$T_{1}=(22+273)K=295\,K$
$P_{2}=265\, mmHg$
$T_{2}=(42+273)K=315\,K$
As $n$ is constant,
$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$ (combined gas law)
$\implies V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$
$=\frac{165\, mmHg\times 754\,mL\times 315\,K}{295\,K\times265\, mmHg}$
$=501\,mL$
