## Chemistry: The Molecular Science (5th Edition)

$P_{1}=165\, mmHg$ $V_{1}=754\,mL$ $T_{1}=(22+273)K=295\,K$ $P_{2}=265\, mmHg$ $T_{2}=(42+273)K=315\,K$ As $n$ is constant, $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$ (combined gas law) $\implies V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$ $=\frac{165\, mmHg\times 754\,mL\times 315\,K}{295\,K\times265\, mmHg}$ $=501\,mL$