Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370a: 25


501 mL

Work Step by Step

$P_{1}=165\, mmHg$ $V_{1}=754\,mL$ $T_{1}=(22+273)K=295\,K$ $P_{2}=265\, mmHg$ $T_{2}=(42+273)K=315\,K$ As $n$ is constant, $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$ (combined gas law) $\implies V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$ $=\frac{165\, mmHg\times 754\,mL\times 315\,K}{295\,K\times265\, mmHg}$ $=501\,mL$
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