## Chemistry: The Molecular Science (5th Edition)

$P_{1}$ = 100. mm Hg $V_{1}$ = 125 mL $V_{2}$ = 200. L According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$ ⇒ $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{100. mm Hg\times125 mL}{200. mL}$ = 62.5 mm Hg