Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370a: 18


62.5 mm Hg

Work Step by Step

$P_{1}$ = 100. mm Hg $V_{1}$ = 125 mL $V_{2}$ = 200. L According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$ ⇒ $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{100. mm Hg\times125 mL}{200. mL}$ = 62.5 mm Hg
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