#### Answer

62.5 mm Hg

#### Work Step by Step

$P_{1}$ = 100. mm Hg
$V_{1}$ = 125 mL
$V_{2}$ = 200. L
According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$
⇒ $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{100. mm Hg\times125 mL}{200. mL}$ = 62.5 mm Hg

Published by
Cengage Learning

ISBN 10:
1285199049

ISBN 13:
978-1-28519-904-7

62.5 mm Hg

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