Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370a: 21


26.5 mL

Work Step by Step

$V_{1}=25.0\,mL$ $T_{1}=(20+273)K= 293\,K$ $T_{2}= (37+273)K=310\,K$ According to Charles's law, $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$ (unchanging P and n) $\implies V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{25.0\,mL\times310\,K}{293\,K}$ $=26.5\,mL$
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