## Chemistry: The Molecular Science (5th Edition)

$V_{1}=25.0\,mL$ $T_{1}=(20+273)K= 293\,K$ $T_{2}= (37+273)K=310\,K$ According to Charles's law, $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$ (unchanging P and n) $\implies V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{25.0\,mL\times310\,K}{293\,K}$ $=26.5\,mL$