Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370a: 26b



Work Step by Step

$n= 42.8\,mol$ (value from 26a) $P=600.\, mmHg\times\frac{1\,atm}{760\, mmHg}=0.7895\,atm$ $T= (-33+273)K= 240.\,K$ $R=0.0821\,L\,atm\,mol^{-1}K^{-1}$ $PV=nRT$ (ideal gas law) $\implies V=\frac{nRT}{P}=\frac{(42.8\,mol)(0.0821\,L\,atm\,mol^{-1}K^{-1})(240.\,K)}{0.7895\,atm}$ $=1.07\times10^{3}\,L$
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