Answer
$1.07\times10^{3}\,L$
Work Step by Step
$n= 42.8\,mol$ (value from 26a)
$P=600.\, mmHg\times\frac{1\,atm}{760\, mmHg}=0.7895\,atm$
$T= (-33+273)K= 240.\,K$
$R=0.0821\,L\,atm\,mol^{-1}K^{-1}$
$PV=nRT$ (ideal gas law)
$\implies V=\frac{nRT}{P}=\frac{(42.8\,mol)(0.0821\,L\,atm\,mol^{-1}K^{-1})(240.\,K)}{0.7895\,atm}$
$=1.07\times10^{3}\,L$
