Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370a: 27


0.507 atm

Work Step by Step

Volume $V=560 \,mL=0.560\,L$ Number of moles $n=\frac{1.55\,g}{131.293\,g/mol}=0.0118\,mol$ Universal gas constant $R= 0.0821\,L\,atm\,mol^{-1}K^{-1}$ Temperature $T=(20 \,+273)K= 293\,K$ Recall that $PV=nRT$ (ideal gas law) $\implies $ Pressure $P= \frac{nRT}{V}$ $=\frac{(0.0118\,mol)(0.0821\,L\,atm\,mol^{-1}K^{-1})(293\,K)}{0.560\,L}$ $=0.507\,atm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.