## Chemistry: The Molecular Science (5th Edition)

$V_{1}=1.0\,L$ $P_{1}=2.0\,atm$ $V_{2}=4.0\,L$ Temperature and amount of gas are constant. Boyle's law states that $P_{1}V_{1}=P_{2}V_{2}$ (unchanging T and n) $\implies P_{2}=\frac{P_{1}V_{1}}{V_{2}}=\frac{2.0\,atm\times1.0\,L}{4.0\,L}$ $=0.50\,atm$