Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 70

Answer

$42.5\ mL$

Work Step by Step

Number of moles of the salt: $2.152\ g\div 105.99\ g/mol=0.02030\ mol$ From stoichiometry: $0.04061\ mol$ of acid. Volume: $0.04061\ mol\div 0.955\ M=0.0425\ L=42.5\ mL$
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