Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 69


$44.6\ mL$

Work Step by Step

Number of moles of the base: $1.45\ g\div 40.00\ g/mol=0.0363\ mol$ From stoichiometry, that's the same number of moles of acid, so: $0.00363\ mol\div 0.812\ M=$ $0.0446\ L=44.6\ mL$
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