## Chemistry and Chemical Reactivity (9th Edition)

$44.6\ mL$
Number of moles of the base: $1.45\ g\div 40.00\ g/mol=0.0363\ mol$ From stoichiometry, that's the same number of moles of acid, so: $0.00363\ mol\div 0.812\ M=$ $0.0446\ L=44.6\ mL$