## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 68

#### Answer

$76.9\ mL$

#### Work Step by Step

Number of moles of NaOH: $35.2\ mL\times 0.546\ M=19.2\ mmol$ From stoichiometry: $9.6\ mmol\ H_2C_2O_4$ Volume required: $9.6\ mmol\div 0.125\ M= 76.9\ mL$

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