## Chemistry and Chemical Reactivity (9th Edition)

Number of moles of the salt: $0.35\ M\times 15.0\ L=5.25\ mol$ From stoichiometry: $5.25\ mol$ of NaOH, $2.63\ mol$ of $Cl_2$ Masses formed: $5.25\ mol\times40.0\ g/mol=210\ g$ of NaOH, $2.63\ mol\times70.91\ g/mol=186\ g$ of $Cl_2$