Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 63


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Work Step by Step

Number of moles of the salt: $0.35\ M\times 15.0\ L=5.25\ mol$ From stoichiometry: $5.25\ mol$ of NaOH, $2.63\ mol$ of $Cl_2$ Masses formed: $5.25\ mol\times40.0\ g/mol=210\ g$ of NaOH, $2.63\ mol\times70.91\ g/mol=186\ g$ of $Cl_2$
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