Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 62


$0.33\ g$

Work Step by Step

Number of moles of the acid: $50.0\ mL \div 0.125\ M=6.25\ mmol$ From stoichiometry, number of moles of acid required: $0.00313\ mol$ Mass required: $0.00313\ mol\times 105.99\ g/mol=0.33\ g$
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