Work Step by Step
Number of moles of the base: $2.50\ g\div171.34\ g/mol=0.0146\ mol$ From stoichiometry, number of moles of acid required: $0.0292\ mol$ Volume required: $0.0292\ mol\div0.109\ M=0.268\ L=268\ mL$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.