Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179e: 61

Answer

$268\ mL$

Work Step by Step

Number of moles of the base: $2.50\ g\div171.34\ g/mol=0.0146\ mol$ From stoichiometry, number of moles of acid required: $0.0292\ mol$ Volume required: $0.0292\ mol\div0.109\ M=0.268\ L=268\ mL$
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