## Chemistry and Chemical Reactivity (9th Edition)

$268\ mL$
Number of moles of the base: $2.50\ g\div171.34\ g/mol=0.0146\ mol$ From stoichiometry, number of moles of acid required: $0.0292\ mol$ Volume required: $0.0292\ mol\div0.109\ M=0.268\ L=268\ mL$