Answer
$1.052\ M$
Work Step by Step
Number of moles of the salt:
$2.150\ g\div 105.99\ g/mol=0.02028\ mol$
From stoichiometry:
$0.04057\ mol$ of acid.
Concentration:
$0.04057\ mol\div 0.03855\ L=1.052\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179f: 71
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