Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179f: 75



Work Step by Step

Number of moles of $KMnO_4$: $0.0123\ M\times 22.25\ mL=0.274\ mmol$ From stoichiometry: $1.37\ mmol$ of iron Mass: $0.00137\ mol\times 55.845\ g/mol=0.0764\ g$ Mass fraction: $0.0764/0.598\times 100\%=12.8\%$
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