Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179f: 73


$104.03\ g/mol$

Work Step by Step

Number of moles of the base: $0.509\ M\times 36.04\ mL=18.34\ mmol$ From stoichiometry: $9.17\ mmol$ of acid. Molar mass: $954\ mg\div 9.17\ mmol=104.03\ g/mol$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.